Changes between Version 1 and Version 2 of HelperFunctions

Timestamp:

Aug 17, 2006, 10:01:57 PM (17 years ago)

Author:

cmlenz

Comment:

Added function pasted on the IrcChannel by Arnar

HelperFunctions

@@ -78 +78 @@
 
 See also the Python Cookbook recipe “[http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/303060 Group a list into sequential n-tuples]”.
+
+=== Example usage ===
+
+{{{
+#!xml
+<table py:with="fields = ['a', 'b', 'c', 'd', 'e']">
+  <tr py:for="row in group(fields, 2)">
+    <td py:for="cell in row">${cell}</td>
+  </tr>
+</table>
+}}}
+
+That should result in the following output:
+
+{{{
+#!xml
+<table>
+  <tr>
+    <td>a</td><td>b</td>
+  </tr><tr>
+    <td>c</td><td>d</td>
+  </tr><tr>
+    <td>e</td><td></td>
+  </tr>
+</table>
+}}}
+
+== countoccurrences() ==
+
+Written by Arnar Birgisson and shared on the IrcChannel.
+
+{{{
+#!python
+def countoccurrences(numbers, minlength=0):
+    """Takes a list of integers numbers, in the range of 0..n and returns
+    a list of integers where i-th item is the number of times i appears in types.
+    
+    If minlength is specified and n+1 < minlength, the returned list is
+    right-padded with zeroes to make it contain minlength items.
+    
+    Examples:
+    >>> countoccurrences([0,3,1,2,1,1,3,5])
+    [1,3,1,2,0,1]
+    >>> countoccurrences([0,3,1,2,1,1,3,5], 10)
+    [1,3,1,2,0,1,0,0,0,0]
+    """
+    # TODO come up with a better name
+    counts = [0] * max(max(numbers)+1, minlength)
+    for x in numbers:
+        counts[x] += 1
+    return counts
+}}}
+
+Example usage:
+
+{{{
+#!xml
+<py:with vars="counts = countoccurrences([p.status.value for p in subdir.job.pages], 3)">
+    <td><span style="color: #e18f01;">${counts[0]}</span></td>
+    <td><span style="color: #249f0b;">${counts[1]}</span></td>
+    <td><span style="color: #ae0a0a;">${counts[2]}</span></td>
+</py:with>
+}}}
+
+----
+See also: MarkupGuide, MarkupRecipes